If y= (e^ m x +e^ -m x ) , then what is d y d x at x=0 equal to?

Step-by-step solution

y= _e (e^ m x +e^ -m x ) d y d x = 1 (e^ m x +e^ -m x ) (e^ m x m+e^ -m x (-m) )= 1 (e^ m x +e^ -m x ) (e^ m x -e^ -m x ) ( d y d x )_ x=0 =0