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NDA 2010
Exam
NDA
Year
2010
Subject
Mathematics
Chapter
Differentiation

NDA 2010 · Mathematics · Differentiation

What is the derivative of ^2 x with respect to ^2 x ?

What is the derivative of sin⁡2x\sin ^2 x with respect to cos⁡2x\cos ^2 x ?

Options

  1. Atan⁡2x\tan ^2 x
  2. Bcot⁡2x\cot ^2 x
  3. C-1
  4. D1

Correct answer

C. -1

Step-by-step solution

\begin{aligned} & \text{ Let } u=\sin ^2 x \\ & \text{and } v=\cos ^2 x \\ & \begin{aligned} \therefore \frac{d u}{d x} & =2 \sin x \cdot \cos x \\ \frac{d u}{d x} & =-2 \cos x \cdot \sin x \\ \therefore \quad \frac{d u}{d v} & =\frac{d u}{d x} \times \frac{d x}{d v} \\ & =\frac{2 \sin x \cdot \cos x}{-2 \sin x \cdot \cos x}=-1\end{aligned}\end{aligned}$
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