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NDA 2022
Exam
NDA
Year
2022
Subject
Mathematics
Chapter
Heights and Distances

NDA 2022 · Mathematics · Heights and Distances

A vertical tower stands on a horizontal plane and is surmounted by...

A vertical tower stands on a horizontal plane and is surmounted by a vertical flagstaff of height hh. At a point on the plane the angles of elevation of the bottom and top of the flagstaff are θ\theta and 2θ2 \theta respectively. What is the height of the tower?

Options

  1. Ahcos⁡θh \cos \theta
  2. Bhsin⁡θh \sin \theta
  3. Chcos⁡2θh \cos 2 \theta
  4. Dhsin⁡2θh \sin 2 \theta

Correct answer

C. hcos⁡2θh \cos 2 \theta

Step-by-step solution

In △PBCtan⁡θ=BCPC⇒PC=BCcot⁡θ...(i)\triangle \mathrm{PBC}\tan \theta=\frac{B C}{P C}\Rightarrow \quad P C=B C \cot \theta...(i) In △PAC\triangle P A Ctan⁡2θ=h+BCPC⇒PCtan⁡2θ=h+BC\begin{aligned} & \tan 2 \theta=\frac{h+B C}{P C} \\ \Rightarrow \quad & P C \tan 2 \theta=h+B C\end{aligned}$\begin{aligned} & \Rightarrow \quad B C \cdot \cot \theta \cdot \frac{2 \tan \theta}{1-\tan ^2 \theta}=h+B C \\ & \Rightarrow \quad \frac{2 B C}{1-\tan ^2 \theta}-B C=h \\ & \Rightarrow \quad \frac{1+\tan ^2 \theta}{1-\tan ^2 \theta} B C=h \\ & \Rightarrow \quad B C=\frac{1-\tan ^2 \theta}{1+\tan ^2 \theta} h=\cos 2 \theta \cdot h\end{aligned}
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