NDA2023MathematicsSequences and SeriesActual
Let a₁, a₂, a₃ be in AP such that a₁+a₅+a₁₀+a₁₅+a₂₀+a₂₅+a₃₀+a₃₄=300 What is a₁+a₅-a₁₀-a₁₅-a₂₀-a₂₅+a₃₀+a₃₄ equal to?
Options
- A0
- B25
- C125
- D250
Correct answer
A. 0
Step-by-step solution
Since, aligned & a₁+a₅-a₁₀-a₁₅-a₂₂-a₂₅+a₃₀+a₃₄ & =a₁+a₁+4 d-a₁-9 d-a₁-14 d-a₁-19 d & =a₁-24 d+a₁+29 d+a₁+33 d & =0 aligned