NDA2017MathematicsSequences and SeriesActual
The value of the product 6^ 1 2 6^ 1 4 6^ 1 8 6^ 1 16 . up to infinite terms is
Options
- A6
- B36
- C216
- D512
Correct answer
A. 6
Step-by-step solution
6^ 1 2 6^ 1 4 6^ 1 8 6^ 1 16 upto infinite terms. =6^ 1 2 + 1 4 + 1 8 + 1 16 + =6 Sum of terms of G.P. is S _ = a 1- r . Here a = 1 2 , r = 1 2 6^ 1 2 + 1 4 + 1 8 + 1 16 + =6^ 1 2 1- 1 2 =6^ 1 2 1 2 =6^1=6 .