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NDA 2013
Exam
NDA
Year
2013
Subject
Mathematics
Chapter
Sequences and Series

NDA 2013 · Mathematics · Sequences and Series

If the numbers n-3,4 n-2,5 n+1 are in AP , what is the value of n ?

If the numbers n−3,4n−2,5n+1n-3,4 n-2,5 n+1 are in AP , what is the value of nn ?

Options

  1. A11
  2. B22
  3. C33
  4. D44

Correct answer

A. 11

Step-by-step solution

∵(n−3),4n−2,5n+1\because(n-3), 4 n-2,5 n+1 are in A.P. 2(4n−2)=(n−3)+5n+1&8n−4=6n−2⇒n=1\begin{aligned}& 2(4 n-2)=(n-3)+5 n+1 \& 8 n-4=6 n-2 \Rightarrow n=1\end{aligned}
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