NDA2011MathematicsSequences and SeriesActual
Which term of the series 1 4 ,- 1 2 , 1, is -128 ?
Options
- A9th
- B10 th
- C11 th
- D12 th
Correct answer
B. 10 th
Step-by-step solution
Since that given series are in G.P Where first term = 1 4 , common ratio =-2 Let -128 is n th term array rlrl & & -128 & = 1 4 (-2)^ n-1 & & -128 4 & =(-2)^ n-1 & & (-2)^9 & =(-2)^ n-1 & n & =9+1=10^ th array