AP EAMCET202021 Sep 2020Morning ShiftMathematicsDeterminantsActual
If ( (0, 2 ) ), then ( | array ccc ( + cosec )^2 & ( - cosec )^2 & 2020 ( + )^2 & ( - )^2 & 2020 ( + )^2 & ( - )^2 & 2020 array |= )
Options
- A1
- B-1
- C0
- D2020
Correct answer
C. 0
Step-by-step solution
Given determinate, where ( (0, 2 ) ) is ( = | array ccc ( + cosec )^2 & ( - cosec )^2 & 2020 ( + )^2 & ( - )^2 & 2020 ( + )^2 & ( - )^2 & 2020 array | ) On applying (C₁ C₁-C₂ ), we get ( = | array ccc 4 & ( - cosec )^2 & 2020 4 & ( - )^2 & 2020 4 & ( - )^2 & 2020 array | ) ( ) Elements of columns (C₁ ) and (C₂ ) are perportional, so ( =0 ) Hence, option (c) is correct.