AP EAMCET202018 Sep 2020Evening ShiftMathematicsDeterminantsActual
Let (M= [ array ll 1 & 1 0 & 1 array ] ) and (N= [ array ll 1 & 0 0 & 2 array ] ). Then (N M¹⁰ N⁻¹= )
Options
- A( [ array ll 1 & 5 0 & 1 array ] )
- B( [ array cc 1 & -5 0 & 1 array ] )
- C( [ array cc 1 & -10 0 & 1 array ] )
- D( [ array cc 1 & 10 0 & 1 array ] )
Correct answer
A. ( [ array ll 1 & 5 0 & 1 array ] )
Step-by-step solution
( aligned M & = [ array ll 1 & 1 0 & 1 array ] M^2 & = [ array ll 1 & 1 0 & 1 array ] [ array ll 1 & 1 0 & 1 array ] M^2 & = [ array ll 1 & 2 0 & 1 array ] M^3 & = [ array ll 1 & 3 0 & 1 array ] & M¹⁰ & = [ array ll 1 & 10 0 & 1 array ] N & = [ array ll 1 & 0 0 & 2 array ] |N| & =2-0=2 Adj ^N & = [ array ll 2 & 0 0 & 1 array ] N⁻¹ & = 1 |N| Adj A N⁻¹ & = 1 2 [ array ll 2 & 0 0 & 1 array ] N⁻¹ & = [ array ll 1 & 0 0 & 1 2 array ] aligned ) Consider, ( aligned N M ¹⁰ N ⁻¹ & = [ array ll 1 & 0 0 & 2 array ] [ array cc