A student wishes to study the cell structure under a light...

In order to increase the resolution, the specimen must be viewed using either shorter wavelength $(\lambda)$ light or through an imaging medium with a relatively high refractive index or with optical components which have a high numerical aperture (NA). thus, resolution of microscope in inversely proportional to the wavelength of the light used. $\Delta$d=$\frac{\lambda}{2 n \sin \theta}$Where, $$\begin{aligned}& \lambda=\text{ wavelength }\\ & n=\text{ refractive index }\\ & \theta=\text{ half angle subtended }\\ & \Deltad=\text{ shortest distance. } \end{aligned}$$