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NEET 2007
Exam
NEET
Year
2007
Subject
Botany
Chapter
Transport in Plants

NEET 2007 · Botany · Transport in Plants

Two cells I and II are contiguous. Cell I has osmotic pressure 10...

Two cells I and II are contiguous. Cell I has osmotic pressure 10 atm10 \mathrm{~atm}. turgor pressure 7 atm7 \mathrm{~atm} and diffusion pressure deficit 3 atm3 \mathrm{~atm}. Cell II has osmotic pressure 8 atm8 \mathrm{~atm}, turgor pressure 3 atm3 \mathrm{~atm} and diffusion pressure deficit 5 atm5 \mathrm{~atm}. The result will be:

Options

  1. Ano movement of water
  2. Bequilibrium between the two
  3. Cmovement of water from cell I to II
  4. Dmovement of water from cell II to I.

Correct answer

C. movement of water from cell I to II

Step-by-step solution

The water moves from a lower diffusion pressure deficit to a higher diffusion, pressure deficit i.e., from A to BB. The cell-to-cell movement of water depends on the DPD, and not on the osmotic pressure and turgor pressure. Related Theory Even though the osmotic pressures are same on both sides of the semi-permeable membrane, the movement of water will take place to equate the DPD on both sides of the membrane. Osmosis takes place from lower DPDD P D (higher water potential) to higher DPD (lower water potential). Therefore, DPD=OP−TPD P D=O P-T P
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