The values of K_ p_1 and K_ p_2 for the reactions (X leftharpoons Y+Z) ...(i) and (A leftharpoons 2 B) ...(ii) are in ratio of 9: 1 . If degree of dissociation of X and A be equal, then total pressure at equilibrium (i)

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Correct answer: C. 36: 1

From equation. ( array lcc & X & leftharpoons & Y & + & Z Initial mole & 10 & & 0 & & 0 mole at equilibrium & (1-a) & & a & & a array ) aligned & K_ p_1 =(p_Y × p_z)/(p_X) & =([(α × p_1)/(1+α)][(α × p_1)/(1+α)])/([(1-α)/(1+α)] p_1) & K_ P_1 =(α^2 p_1)/(1-α^2) aligned From equation ( array lcc & A & leftharpoons & 2 B Initial mole & 10 & & 0 mole at equilibrium & (1-a) & & 2 a array ) aligned & K_ p_2 =([(2 α)/(1+α) · p_2]^2)/([(1-α)/(1+α)] p_2)=(4 α^2 p_2)/(1-α^2) aligned From Eqs (i) and (ii) K_ P_1 K_ P_2 =(p_1)/(4 p_2) array ll & (9)/(1)=(p_1)/(4 p_2) & (p_1)/(p_2)=(36)/(1) array

The values of K_ p_1 and K_ p_2 for the reactions (X leftharpoons...

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