NEET2022ChemistryChemical KineticsActual
For a chemical reaction 4 ~A +3 ~B 6 C +9 D rate of formation of C is 6 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ and rate of disappearance of A is 4 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ . The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be:
Options
- A1 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ and 30 10⁻² ~mol ~L ⁻¹
- B10 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ and 10 10⁻² ~mol ~L ⁻¹
- C1 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ and 10 10⁻² ~mol ~L ⁻¹
- D10 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ and 30 10⁻² ~mol ~L ⁻¹
Correct answer
A. 1 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ and 30 10⁻² ~mol ~L ⁻¹
Step-by-step solution
aligned & Explanation: 4 ~A +3 ~B 6 C +9 D & aligned Rate of reaction & =- 1 4 d[ ~A ] d t =- 1 3 d[ ~B ] d t & = 1 6 d[ C ] d t = 1 9 d[ D ] d t aligned aligned Rate of reaction = Rate of formation of C . aligned r & = 1 6 d[ C ] d t = 1 6 6 10⁻² & =1 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ aligned Also, rate of reaction = Rate of disappearance of B aligned r & =- 1 3 d[ ~B ] d t = d[ ~B ] d t =3 r & =3 10⁻² ~mol ~L ⁻¹ ~s ⁻¹ aligned Consumption of B in 10 seconds =3 10⁻² 10 =30 10⁻² ~mol ~L ⁻¹