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NEET 2017
Exam
NEET
Year
2017
Subject
Chemistry
Chapter
Chemical Kinetics

NEET 2017 · Chemistry · Chemical Kinetics

Mechanism of a hypothetical reaction X _ 2 + Y _ 2 → 2XY is given...

Mechanism of a hypothetical reaction X2+Y2→2XY{X}_{2} + {Y}_{2} \to 2XY is given below:

(i) X2→X+X(fast){X}_{2} \to X + X\left(fast\right)

(ii) X+Y2⇌XY+Y(slow)X + {Y}_{2} ⇌ XY + Y\left(slow\right)

(iii) X+Y→XY(fast)X + Y \to XY\left(fast\right)

The overall order of the reaction will be

Options

  1. A11
  2. B22
  3. C00
  4. D1.51 . 5

Correct answer

D. 1.51 . 5

Step-by-step solution

The solution of this question is given by assuming step (i)( i ) to be reversible which is not given in question

Overallrate = Rateofsloweststep ( ii )<br/><br/><br /><br />= k\left[X\right]\left[{Y}_{2}\right]............( i )<br/><br/>K=rateconstantofstep<br /><br />K=rate constant of step( ii )<br/><br/>Assumingstep<br /><br />Assuming step( i )tobereversible,itsequilibriumconstant,<br/><br/>to be reversible, its equilibrium constant,<br /><br />{k}_{eq} = \dfrac{{\left[X\right]}^{2}}{\left[{X}_{2}\right]} ⇒ \left[X\right] = {k}_{eq}^{\dfrac{1}{2}}{\left[{X}_{2}\right]}^{\dfrac{1}{2}}..........( ii )<br/><br/>Put<br /><br />Put( ii )inin( i )<br/><br/>Rate<br /><br />Rate= k{k}_{eq}^{\dfrac{1}{2}}{\left[{X}_{2}\right]}^{\dfrac{1}{2}}\left[{Y}_{2}\right]<br/><br/>Overallorder<br /><br />Overall order= \dfrac{1}{2} + 1 = \dfrac{3}{2}
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