NEET 2017
- Exam
- NEET
- Year
- 2017
- Subject
- Chemistry
- Chapter
- Chemical Kinetics
NEET 2017 · Chemistry · Chemical Kinetics
Mechanism of a hypothetical reaction X _ 2 + Y _ 2 → 2XY is given...
Mechanism of a hypothetical reaction is given below:
(i)
(ii)
(iii)
The overall order of the reaction will be
(i)
(ii)
(iii)
The overall order of the reaction will be
Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
The solution of this question is given by assuming step to be reversible which is not given in question
Overallrate = Rateofsloweststep ( ii )= k\left[X\right]\left[{Y}_{2}\right]( i )( ii )( i ){k}_{eq} = \dfrac{{\left[X\right]}^{2}}{\left[{X}_{2}\right]} ⇒ \left[X\right] = {k}_{eq}^{\dfrac{1}{2}}{\left[{X}_{2}\right]}^{\dfrac{1}{2}}( ii )( ii )( i )= k{k}_{eq}^{\dfrac{1}{2}}{\left[{X}_{2}\right]}^{\dfrac{1}{2}}\left[{Y}_{2}\right]= \dfrac{1}{2} + 1 = \dfrac{3}{2}
Overallrate = Rateofsloweststep ( ii )= k\left[X\right]\left[{Y}_{2}\right]( i )( ii )( i ){k}_{eq} = \dfrac{{\left[X\right]}^{2}}{\left[{X}_{2}\right]} ⇒ \left[X\right] = {k}_{eq}^{\dfrac{1}{2}}{\left[{X}_{2}\right]}^{\dfrac{1}{2}}( ii )( ii )( i )= k{k}_{eq}^{\dfrac{1}{2}}{\left[{X}_{2}\right]}^{\dfrac{1}{2}}\left[{Y}_{2}\right]= \dfrac{1}{2} + 1 = \dfrac{3}{2}