NEET2009ChemistryChemical KineticsActual
For the reaction, A+B products, it is observed that (1) On doubling the initial concentration of A only, the rate of reaction is also doubled and (2) On doubling the initial concentrations of both A and B , there is a change by a factor of 8 in the rate of the reaction. The rate of this reaction is, given by
Options
- Arate =k[A]^2[ ~B ]
- Brate =k[A][B]^2
- Crate = k [ A ]^2[ ~B ]^2
- Drate =k[ ~A ][ B ]
Correct answer
B. rate =k[A][B]^2
Step-by-step solution
For the reaction, A + B Products On doubling the initial concentration of A only, the rate of reaction is also doubled, therefore Rate [ A ]^1 Let initially rate law is Rate =k[A][B]^y If concentration of and both are doubled, the rate gets changed by a factor of 8 . array r 8 Rate = k [2 ~A ][2 ~B ]^ y ( iii) [ Rate [ A ]^1 ] array Dividing Eq. (iii) by Eq. (ii), aligned & 8=2 2^y & 4=2^y & y =2 & aligned Hence, rate law is, rate = k [ A ][ B ]^2