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NEET 2009
Exam
NEET
Year
2009
Subject
Chemistry
Chapter
Chemical Kinetics

NEET 2009 · Chemistry · Chemical Kinetics

For the reaction, N_2+3 H_2 arrow 2 NH_3 , If d[NH_3] dt =2 × 10^...

For the reaction, N2+3H2→2NH3\mathrm{N}_2+3 \mathrm{H}_2 \rightarrow 2 \mathrm{NH}_3, If d[NH3]dt=2×10−4 mol L−1 s−1\frac{\mathrm{d}\left[\mathrm{NH}_3\right]}{\mathrm{dt}}=2 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}, The value of −d[H2]dt\frac{-\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}} would be -

Options

  1. A1×10−4 mol L−1 s−11 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}
  2. B3×10−4 mol L−1 s−13 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}
  3. C4×10−4 mol L−1 s−14 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}
  4. D6×10−4 mol L−1 s−16 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}

Correct answer

B. 3×10−4 mol L−1 s−13 \times 10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}

Step-by-step solution

13−d[H2]dt=12[NH3]dt−d[H2]dt=32d[NH3]dt−d[H2]dt=32×2×10−4=3×10−4 mol L−1 s−1\begin{aligned}& \frac{1}{3} \frac{-\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=\frac{1}{2} \frac{\left[\mathrm{NH}_3\right]}{\mathrm{dt}}\\ & \frac{-\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=\frac{3}{2} \frac{\mathrm{d}\left[\mathrm{NH}_3\right]}{\mathrm{dt}}\\ & \frac{-\mathrm{d}\left[\mathrm{H}_2\right]}{\mathrm{dt}}=\frac{3}{2} \times2 \times10^{-4} \\ & =3 \times10^{-4} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}\\ & \end{aligned}
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