NEET2008ChemistryChemical KineticsActual
The rate constants k ₁ and k ₂ for two different reactions are 10¹⁶ e ^ -2000 / T and 10¹⁵ e ^ -1000 / T respectively. The temperature at which k ₁= k ₂ is
Options
- A1000 2.303 ~K
- B1000 ~K
- C2000 2.303 ~K
- D2000 ~K
Correct answer
A. 1000 2.303 ~K
Step-by-step solution
K₁=10¹⁶ e ^ - 2000 T or K ₁=16- 2000 2.303 ~T K₂=10¹⁵ e^ 1000 T or K₂=15- 1000 2.303 ~T If T = 1000 2.303 ~K , then K ₁= K ₂