If 60 % , of a first order reaction was completed in 60 minutes, 50 % of the same reaction would be completed in approximately: ( 4=0.60, 5=0.69)

Step-by-step solution

For a first order reaction k= 2.303 t a a-x When t=60 and x=60 % aligned k & = 2.303 60 100 100-60 & = 2.303 60 100 40 & =0.0153 aligned Now, aligned t^ 1 / 2 & = 2.303 0.0153 100 100-50 & = 2.303 0.0153 2 & = 2.303 0.0153 0.3010 & =45.31 ~min aligned