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NEET 2006
Exam
NEET
Year
2006
Subject
Chemistry
Chapter
Chemical Kinetics

NEET 2006 · Chemistry · Chemical Kinetics

Consider the reaction: N_ 2(g) +3 H_ 2(g) arrow 2 NH_ 3(g) The...

Consider the reaction: N2(g)+3H2(g)→\mathrm{N}_{2(g)}+3 \mathrm{H}_{2(g)} \rightarrow 2NH3(g)2 \mathrm{NH}_{3(g)} The equality relationship between d[NH3]dt\frac{d\left[\mathrm{NH}_3\right]}{d t} and −d[H2]dt-\frac{d\left[\mathrm{H}_2\right]}{d t} is:

Options

  1. Ad[NH3]dt=−d[H2]dt\frac{d\left[\mathrm{NH}_3\right]}{d t}=-\frac{d\left[\mathrm{H}_2\right]}{d t}
  2. Bd[NH3]dt=−13d[H2]dt\frac{d\left[\mathrm{NH}_3\right]}{d t}=-\frac{1}{3} \frac{d\left[\mathrm{H}_2\right]}{d t}
  3. C+d[NH]3dt=−23d[H2]dt+\frac{d[\mathrm{NH}]_3}{d t}=-\frac{2}{3} \frac{d\left[\mathrm{H}_2\right]}{d t}
  4. D+d[NH3]dt=−32d[H2]dt+\frac{d\left[\mathrm{NH}_3\right]}{d t}=-\frac{3}{2} \frac{d\left[\mathrm{H}_2\right]}{d t}

Correct answer

C. +d[NH]3dt=−23d[H2]dt+\frac{d[\mathrm{NH}]_3}{d t}=-\frac{2}{3} \frac{d\left[\mathrm{H}_2\right]}{d t}

Step-by-step solution

For the reaction \begin{aligned} \mathrm{N}_2(g)+3 \mathrm{H}_2(g) & \rightarrow 2 \mathrm{NH}_3(g) \\ \frac{-d\left[\mathrm{~N}_2\right]}{d t} & =-\frac{1}{3} \frac{d}{d t}\left[\mathrm{H}_2\right] \\ & =\frac{1}{2} \frac{d}{d t}\left(\left[\mathrm{NH}_3\right]\right) \\ \therefore \frac{d}{d t}\left(\left[\mathrm{NH}_3\right]\right) & =-\frac{2}{3} \frac{d}{d t}\left[\mathrm{H}_2\right] \end{aligned}
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