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NEET 2004
Exam
NEET
Year
2004
Subject
Chemistry
Chapter
Chemical Kinetics

NEET 2004 · Chemistry · Chemical Kinetics

The rate of a first order reaction is 1.5 × 10^ -2 ~mol ~L^ -1...

The rate of a first order reaction is 1.5×1.5 \times 10−2 mol L−1 min−110^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1} at 0.5M0.5 \mathrm{M} concentration of the reactant. The half life of the reaction is:The rate of a first order reaction is 1.5 × 10^ -2 ~mol ~L^ -1 ~min^ -1 at 0.5 M concentration of the reactant. TheThe rate of a first order reaction is 1.5 × 10^ -2 ~mol ~L^ -1 ~min^ -1 at 0.5 M concentration of the reactant. The

Options

  1. A0.383 min0.383 \mathrm{~min}
  2. B23.1 min23.1 \mathrm{~min}
  3. C8.73 min8.73 \mathrm{~min}
  4. D7.53 min7.53 \mathrm{~min}

Correct answer

B. 23.1 min23.1 \mathrm{~min}

Step-by-step solution

Let the reaction be A⟶k Product  Rate =k[ A]1.5×10−2 molL −1min−1=k[0.5]k=1.5×10−20.5=3×10−2 min−1t1/2=0.693k⇒t1/2=0.6933×10−2=0.231×102 min⇒t1/2=23.1 min\begin{aligned}& \mathrm{A} \stackrel{k}{\longrightarrow} \text{ Product }\\ & \text{ Rate }=k[\mathrm{~A}]\\ & 1.5 \times10^{-2} \mathrm{~mol} \mathrm{\textrm {L } ^ { - 1 } \mathrm{ min } ^ { - 1 } = k [ 0 . 5 ]}\\ & k=\frac{1.5 \times 10^{-2}}{0.5}\\ &=3 \times10^{-2} \mathrm{~min}^{-1}\\ & t_{1/2}=\frac{0.693}{k}\\ & \Rightarrow \quad t_{1/2}=\frac{0.693}{3 \times 10^{-2}}\\ &=0.231 \times10^2 \mathrm{~min}\\ & \Rightarrow \quad t_{1/2}=23.1 \mathrm{~min} \end{aligned}Related Theory Decay profiles for first-order reactions with large and small rate constants The rate of a first order reaction is 1.5 × 10^ -2 ~mol ~L^ -1 ~min^ -1 at 0.5 M concentration of the reactant. The
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