Reaction A B follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of B is 1 hour. What is the time taken for conversion of 0.9 mole of A to produce 0.675 mole of B ?

Step-by-step solution

For first order reaction, ( k = 2.303 t a a - x .(1) ) Where (k ) is rate constant when 0.8 mol of (A ) produces 0.6 mol of (B ) then, (0.8-0.6=0.2 ) moles of A is left . final moles ( A = a - x =0.2 ) initial moles ( a =0.8 ) ( aligned & t = 2.303 k 0.8 o .2 & k = 2.303 1 [4] . . (2) & k =2.303 0.6020 & k =1.3865 . .(3) aligned ) In second case, 0.9 moles of A produces 0.675 moles of (B ) so remaining moles of (A ) are (0.9-0.675=0.225 ) final moles of ( A = a - x =0.225 ) initial mole (=0.9 ) By using first order