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NEET 2002
Exam
NEET
Year
2002
Subject
Chemistry
Chapter
Chemical Kinetics

NEET 2002 · Chemistry · Chemical Kinetics

3 ~A arrow 2 ~B , then the rate of reaction +d[~B] d t is equal to:

3 A→2 B3 \mathrm{~A} \rightarrow 2 \mathrm{~B}, then the rate of reaction +d[ B]dt\frac{+d[\mathrm{~B}]}{d t} is equal to:

Options

  1. A−32d[ A]dt-\frac{3}{2} \frac{d[\mathrm{~A}]}{d t}
  2. B−23d[ A]dt-\frac{2}{3} \frac{d[\mathrm{~A}]}{d t}
  3. C−12d[ A]dt-\frac{1}{2} \frac{d[\mathrm{~A}]}{d t}
  4. D2d[A]dt2 \frac{d[A]}{d t}

Correct answer

B. −23d[ A]dt-\frac{2}{3} \frac{d[\mathrm{~A}]}{d t}

Step-by-step solution

For the reaction, 3A→2B Rate =−13d[A]dt=+12d[B]dt∴+d[B]dt=−23d[A]dt\begin{gathered} 3 \mathrm{ A} \rightarrow 2 \mathrm{ B} \\ \text{ Rate }=-\frac{1}{3} \frac{d[\mathrm{ A}]}{d t}=+\frac{1}{2} \frac{d[\mathrm{ B}]}{d t} \\ \therefore+\frac{d[\mathrm{ B}]}{d t}=-\frac{2}{3} \frac{d[\mathrm{ A}]}{d t} \end{gathered}
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