NEET2017Chemistryd and f Block ElementsActual
It is because of the inability of ns 2 electrons of the valence shell to participate in bonding that
Options
- ASn 2 + is reducing while Pb 4 + is oxidizing.
- BSn 2 + is oxidizing while Pb 4 + is reducing.
- CSn 2 + and Pb 2 + are both oxidizing and reducing.
- DSn 4 + is reducing while Pb 4 + is oxidizing.
Correct answer
A. Sn 2 + is reducing while Pb 4 + is oxidizing.
Step-by-step solution
The inability of ns 2 electrons of the valence shell to participate in bonding on moving down the group in heavier p - block elements is called inert pair effect. As a result,   Pb ( II )   is more stable than Pb ( IV ) Sn ( IV ) is more stable than Sn ( II ) ∴       Pb ( IV ) is easily reduced to Pb ( II ) . ∴       Pb ( IV ) is an oxidizing agent. Sn ( II ) is easily oxidized to Sn ( IV ) ∴         Sn ( II )   is reducing agent.