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NEET 2015
Exam
NEET
Year
2015
Subject
Chemistry
Chapter
d and f Block Elements

NEET 2015 · Chemistry · d and f Block Elements

Spin only magnetic moment 2 .84 BM is given by: (Atomic Number of...

Spin only magnetic moment 2.84BM2 .84 BM is given by:

(Atomic Number of Ni=28,Ti=22,Cr=24,Co=27Ni =28, Ti =22, Cr =24, Co =27)

Options

  1. ANi2+{Ni}^{2 +}
  2. BTi3+{Ti}^{3 +}
  3. CCr2+{Cr}^{2 +}
  4. DCo2+{Co}^{2 +}

Correct answer

A. Ni2+{Ni}^{2 +}

Step-by-step solution

\mu=n(n+2)=2.84⇒n=2\text{\mu} = \sqrt{\text{n}( \text{n} + 2 )} = 2.84 ⇒ \text{n} = 2

electronic configuration of Ni+2=1s22s22p63s23p63d8e−{\text{Ni}}^{+ 2} = 1{\text{s}}^{2} 2{\text{s}}^{2} 2{\text{p}}^{6} 3{\text{s}}^{2} 3{\text{p}}^{6} 3{\text{d}}^{8}{\text{e}}^{-} having two unpaired electrons

electron configuration of Ti3+=1s22s22p63s23p63d1\text{T}{\text{i}}^{3 +} = 1{\text{s}}^{2} 2{\text{s}}^{2} 2{\text{p}}^{6} 3{\text{s}}^{2} 3{\text{p}}^{6} 3{\text{d}}^{1} only one unpaired electron

electron configuration of Cr2+=1s22s22p63s23p63d4\text{C}{\text{r}}^{2 +} = 1{\text{s}}^{2} 2{\text{s}}^{2} 2{\text{p}}^{6} 3{\text{s}}^{2} 3{\text{p}}^{6} 3{\text{d}}^{4} having four unpaired electrons

electron configuration of Co+2=1s22s22p63s23p63d7\text{C}{\text{o}}^{+ 2} = 1{\text{s}}^{2} 2{\text{s}}^{2} 2{\text{p}}^{6} 3{\text{s}}^{2} 3{\text{p}}^{6} 3{\text{d}}^{7} having three unpaired electrons.
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