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NEET 2013
Exam
NEET
Year
2013
Subject
Chemistry
Chapter
d and f Block Elements

NEET 2013 · Chemistry · d and f Block Elements

KMnO_4 can be prepared from K_2 MnO_4 as per reaction (3 MnO_2^ 2-...

KMnO4\mathrm{KMnO}_4 can be prepared from K2MnO4\mathrm{K}_2 \mathrm{MnO}_4 as per reaction (3 \mathrm{MnO}_2^{2-}+2 \mathrm{H}_2 \mathrm{O} \rightleftharpoons 2 \mathrm{MnO}_4^{-}+\mathrm{MnO}_2+4 \mathrm{OH}^{-}). The reaction can go to completion by removing OH−\mathrm{OH}^{-}ions by adding

Options

  1. AHCl\mathrm{HCl}
  2. BKOH\mathrm{KOH}
  3. CCO2\mathrm{CO}_2
  4. DSO2\mathrm{SO}_2

Correct answer

D. SO2\mathrm{SO}_2

Step-by-step solution

Since, OH−\mathrm{OH}^{-}are generated from weak acid (H2O)\left(\mathrm{H}_2 \mathrm{O}\right), a weak acid \left(\right.likeCO2)like \left.\mathrm{CO}_2\right) should be used to remove it because of strong acid (HCl)(\mathrm{HCl}) reverse the reaction. KOH\mathrm{KOH} increases the concentration of OH−\mathrm{OH}^{-}, thus again shifts the reaction in backward side. CO2\mathrm{CO}_2 combines with OH−\mathrm{OH}^{-}to give carbonate which is easily removed. SO2\mathrm{SO}_2 reacts with water to give strong acid, so it cannot be used.
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