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NEET 2005
Exam
NEET
Year
2005
Subject
Chemistry
Chapter
d and f Block Elements

NEET 2005 · Chemistry · d and f Block Elements

The aqueous solution containing which one of the following ions...

The aqueous solution containing which one of the following ions will be colourless? (Atomic number : Sc=21,Fe=26,Ti=\mathrm{Sc}=21, \mathrm{Fe}=26, \mathrm{Ti}= 22,Mn=2522, \mathrm{Mn}=25)

Options

  1. ASc3+\mathrm{Sc}^{3+}
  2. BFe2+\mathrm{Fe}^{2+}
  3. CTi3+\mathrm{Ti}^{3+}
  4. DMn2+\mathrm{Mn}^{2+}

Correct answer

A. Sc3+\mathrm{Sc}^{3+}

Step-by-step solution

(
IonNo.of</td></tr><tr><td>Electrons\begin{array}{c} No. of</td></tr><tr><td>Electrons \end{array}Electronic</td></tr><tr><td>Configuration\begin{array}{c} Electronic</td></tr><tr><td>Configuration \end{array}Electronic Configuration in boxNo.of</td></tr><tr><td>Unpaired\begin{array}{c} No. of</td></tr><tr><td>Unpaired \end{array}Magnetic</td></tr><tr><td>Nature\begin{array}{c} Magnetic</td></tr><tr><td>Nature \end{array}MagneticMo−</td></tr><tr><td>ment(BM)</td></tr><tr><td>μ=n(n+2)\begin{array}{c} Magnetic Mo-</td></tr><tr><td>ment (BM)</td></tr><tr><td>\mu=\sqrt{n(\boldsymbol{n}+2)} \end{array}
Sc^{3+}18{[Ar] 3 d^0 4 s^0}[Ar] </td><td></td><td></td><td></td><td></td></tr><tr><td>\begin{array}{|l|l|l|l|l|}</td><td></td><td></td><td></td><td></td></tr><tr><td>\end{array}</td></tr><tr><td>\begin{array}{|l|}</td></tr><tr><td>\end{array}</td><td>0</td><td>Diamagnetic</td><td>0</td></tr><tr><td>Ti3+</td><td>22</td><td>[Ar]3d44s0</td><td>[Ar]</td><td>0</td><td>Diamagnetic</td><td>0</td></tr><tr><td>Ti^{3+}</td><td>22</td><td>{[Ar] 3 d^4 4 s^0}</td><td>[Ar]↑</td><td></td><td></td><td></td><td></td></tr><tr><td>\begin{array}{|l|l|l|l|l|} \uparrow</td><td></td><td></td><td></td><td></td></tr><tr><td>\end{array}$\begin{array}{|l|}</td></tr><tr><td>\end{array}</td><td>1</td><td>Paramagnetic</td><td>1.73</td></tr><tr><td>Mn2+</td><td>23</td><td>[Ar]3d54s0</td><td>[Ar]</td><td>1</td><td>Paramagnetic</td><td>1.73</td></tr><tr><td>Mn^{2+}</td><td>23</td><td>{[Ar] 3 d^5 4 s^0}</td><td>[Ar]↑</td><td>↑</td><td>↑</td><td>↑</td><td>↑</td></tr><tr><td>\begin{array}{|l|l|l|l|l|} \uparrow</td><td>\uparrow</td><td>\uparrow</td><td>\uparrow</td><td>\uparrow</td></tr><tr><td>\end{array}$\begin{array}{|l|}</td></tr><tr><td>\end{array}</td><td>5</td><td>Paramagnetic</td><td>5.92</td></tr><tr><td>Fe2+</td><td>24</td><td>[Ar]3d64s0</td><td>[Ar]</td><td>5</td><td>Paramagnetic</td><td>5.92</td></tr><tr><td>Fe^{2+}</td><td>24</td><td>{[Ar] 3 d^6 4 s^0}</td><td>[Ar]↑↓</td><td>↑</td><td>↑</td><td>↑</td><td>↑</td></tr><tr><td>\begin{array}{|l|l|l|l|l|} \uparrow \downarrow</td><td>\uparrow</td><td>\uparrow</td><td>\uparrow</td><td>\uparrow</td></tr><tr><td>\end{array}</td></tr><tr><td>\begin{array}{|l|}</td></tr><tr><td>\end{array}$4Paramagnetic4.9
)Related Theory Because of the relatively high forces of attraction among the water molecules due to intermolecular hydrogen bonding, water has a higher surface tension than most other liquids. Related Theory Magnetic properties arise from the spin and orbital angular momentum of the electrons contained in a compound. Compounds are diamagnetic when they contain no unpaired electrons.Practice d and f Block Elements on Quantrex Academy →

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