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NEET 2008
Exam
NEET
Year
2008
Subject
Chemistry
Chapter
Environmental Chemistry

NEET 2008 · Chemistry · Environmental Chemistry

On the basis of the following (E^ ) values, the strongest oxidizing...

On the basis of the following (E^{\circ}) values, the strongest oxidizing agent is :- [Fe(CN)6]4−→[Fe(CN)6]3−+e−1,E∘=−0.35 VFe2+→Fe3++e−1;E∘=−0.77 V\begin{aligned} & {\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}+e^{-1}, \mathrm{E}^{\circ}=-0.35 \mathrm{~V}} \\ & \mathrm{Fe}^{2+} \rightarrow \mathrm{Fe}^{3+}+e^{-1} ; \quad \mathrm{E}^{\circ}=-0.77 \mathrm{~V} \end{aligned})$

Options

  1. A[Fe(CN)6]4−\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-}
  2. BFe2+\mathrm{Fe}^{2+}
  3. CFe3+\mathrm{Fe}^{3+}
  4. D[Fe(CN)6]3−\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}

Correct answer

C. Fe3+\mathrm{Fe}^{3+}

Step-by-step solution

Key Idea : Oxidised form + ne e−→e^{-} \rightarrow Reduced form The substances which have lower reduction substances which have higher reduction potential are stronger oxidising agent. [Fe(CN)6]3−+e−→[Fe(CN)6]4−;E∘=0.35 VFe3++e−→Fe2+;E∘=0.77 V\begin{array}{l} {\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{3-}+e^{-}} \rightarrow\left[\mathrm{Fe}(\mathrm{CN})_6\right]^{4-} ; E^{\circ}=0.35 \mathrm{~V} \\ \mathrm{Fe}^{3+}+e^{-} \rightarrow \mathrm{Fe}^{2+} ; E^{\circ}=0.77 \mathrm{~V} \end{array} The reduction potential of Fe3+/Fe2+\mathrm{Fe}^{3+} / \mathrm{Fe}^{2+} is higher, hence Fe3+\mathrm{Fe}^{3+} is strongest oxidising agent.
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