A compound X contains 32 \% of A, 20 \% of B and remaining...

$<table class="qx-match-list qx-match-table" border="1" cellpadding="6" cellspacing="0"><tr><td>Element</td><td>$$\begin{array}{c} Mass</td></tr><tr><td>percentage \%\end{array}$$</td><td>$$\begin{array}{c} No. of</td></tr><tr><td>moles \end{array}$$$</td><td>$$\begin{array}{c} No. of moles /Smallest number \end{array}$$</td><td>$$\begin{array}{c} Simplest wholenumber \end{array}</td></tr><tr><td>A</td><td>32 \%</td><td>\frac{32}{64}=\frac{1}{2}</td><td>\frac{1}{2} \times 2</td><td>=1</td></tr><tr><td>B</td><td>20 \%</td><td>\frac{20}{40}=\frac{1}{2}</td><td>\frac{1}{2} \times 2</td><td>=1</td></tr><tr><td>C</td><td>48 \%</td><td>\frac{48}{32}=\frac{3}{2}</td><td>\frac{3}{2} \times 2</td><td>=3</td></tr></table> So, empirical formula of$X=\begin{array}{clll}A & : & B & \text{ C } \\ 1 & : & 1 & :\end{array}$$\therefore$ The correct empirical formula of compound X is \mathrm{ABC}_3$