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NEET2024ChemistrySome Basic Concepts of ChemistryActual

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to

Options

  1. A250 mg
  2. BZero mg
  3. C200 mg
  4. D750 mg

Correct answer

A. 250 mg

Step-by-step solution

aligned & M = W 1000 . M ₂ V (in mL ) & W = . M M ₂ V (in mL ) 1000 = 0.75 36.5 25 1000 &=0.684 ~g (Mass of HCl ) & 36.5 ~g HCl + 40 ~g NaOH HCl + NaOH aligned 36.5 g HCl reacts with NaOH =40 ~g 0.684 g HCl reacts with NaOH = 40 36.5 0.684 0.750 ~g Amount of NaOH left =1 ~g -0.750 ~g =0.250 ~g =250 mg

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