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NEET 2024
Exam
NEET
Year
2024
Subject
Chemistry
Chapter
Some Basic Concepts of Chemistry

NEET 2024 · Chemistry · Some Basic Concepts of Chemistry

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl...

1 gram of sodium hydroxide was treated with 25 mL of 0.75 M HCl solution, the mass of sodium hydroxide left unreacted is equal to

Options

  1. A250 mg
  2. BZero mg
  3. C200 mg
  4. D750 mg

Correct answer

A. 250 mg

Step-by-step solution

M=W×1000M2×V (in mL)W=M×M2×V (in mL)1000=0.75×36.5×251000=0.684 g (Mass of  HCl)HCl36.5 g+NaOH40 g⟶HCl+NaOH\begin{aligned} & \mathrm{M}=\frac{\mathrm{W} \times 1000}{\left.\mathrm{M}_2 \times \mathrm{V} \text{ (in } \mathrm{mL}\right)} \\ & \mathrm{W}=\frac{\left.\mathrm{M} \times \mathrm{M}_2 \times \mathrm{V} \text{ (in } \mathrm{mL}\right)}{1000}=\frac{0.75 \times 36.5 \times 25}{1000} \\ &=0.684 \mathrm{~g} \text{ (Mass\text{ of } } \mathrm{HCl}) \\ & \underset{36.5 \mathrm{~g}}{\mathrm{HCl}}+\underset{40 \mathrm{~g}}{\mathrm{NaOH}} \longrightarrow \mathrm{HCl}+\mathrm{NaOH} \end{aligned} 36.5 g HCl reacts with NaOH=40 g0.684gHClreacts\mathrm{NaOH}=40 \mathrm{~g} 0.684 g HCl reacts with NaOH=4036.5\mathrm{NaOH}=\frac{40}{36.5} \times 0.684 \simeq 0.750  g\mathrm{~g} Amount of NaOH left =1 g−0.750 g=0.250 g=250mg=1 \mathrm{~g}-0.750 \mathrm{~g}=0.250 \mathrm{~g}=250 \mathrm{mg}
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