5 ~L of 1 M NaOH solution is mixed with 3 ~L of 0.5 M NaOH solution. Find out the molarity of the resultant solution:

Correct answer: C. 0.73 M 2.5 L 1 M Naoh with 3 L 0.5 MNaOH . Intially, Number of moles in 2.5 ~L , aligned 1 M NaOH & =2.5 × 1 & =2.5 moles aligned Number of moles in 3 ~L, 0.5 M NaOH=3 × 0.5=1.5 moles. Total number of moles in final mixture =2.5+1.5=4.0 moles . The total volume of solution =2.5+3=5.5 ~L aligned & Molarity of final solution =(4)/(5.5) & =0.728 M aligned

NEET 2002

Exam: NEET
Year: 2002
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry

NEET 2002 · Chemistry · Some Basic Concepts of Chemistry

5 ~L of 1 M NaOH solution is mixed with 3 ~L of 0.5 M NaOH...

5 \mathrm{~L}

1 \mathrm{M} \mathrm{NaOH}

solution is mixed with

3 \mathrm{~L}

0.5 \mathrm{M} \mathrm{NaOH}

solution. Find out the molarity of the resultant solution:

Options

A $0.80 \mathrm{M}$
B $1.0 \mathrm{M}$
C $0.73 \mathrm{M}$
D $0.50 \mathrm{M}$

Correct answer

C. $0.73 \mathrm{M}$

Step-by-step solution

2.5 L

1 \mathrm{M}

Naoh with 3 L

0.5 \mathrm{M}\mathrm{NaOH}

. Intially, Number of moles in

2.5 \mathrm{~L}

\begin{aligned} 1 \mathrm{M} \mathrm{NaOH} & =2.5 \times 1 \\ & =2.5 \text{ moles } \end{aligned}

Number of moles in

3 \mathrm{~L}, 0.5 \mathrm{M} \mathrm{NaOH}=3 \times 0.5=1.5

moles.

\Rightarrow

Total number of moles in final mixture

=2.5+1.5=4.0

moles . The total volume of solution

=2.5+3=5.5 \mathrm{~L}

\begin{aligned} & \Rightarrow \text{ Molarity of final solution }=\frac{4}{5.5} \\ & =0.728 \mathrm{M} \end{aligned}

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