The percentage of C, H and N in an organic compound are 40 \%, 13.3...

The percentage of

\mathrm{C}, \mathrm{H}

and

\mathrm{N}

in an organic compound are

40 \%, 13.3 \%

and

46.7 \%

, respectively, then the empirical formula is: $The percentage of C, H and N in an organic compound are 40 \%, 13.3 \% and 46.7 \% , respectively, then the empirical$ $The percentage of C, H and N in an organic compound are 40 \%, 13.3 \% and 46.7 \% , respectively, then the empirical$

Options

A $\mathrm{C}_3 \mathrm{H}_{13} \mathrm{~N}_3$
B $\mathrm{CH}_2 \mathrm{~N}$
C $\mathrm{CH}_4 \mathrm{~N}$
D $\mathrm{CH}_6 \mathrm{~N}$

Correct answer

C. $\mathrm{CH}_4 \mathrm{~N}$

Step-by-step solution

$The percentage of C, H and N in an organic compound are 40 \%, 13.3 \% and 46.7 \% , respectively, then the empirical$
$The percentage of C, H and N in an organic compound are 40 \%, 13.3 \% and 46.7 \% , respectively, then the empirical$ Hence, empirical formula of compound is

\mathrm{CH}_4 \mathrm{~N}

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