NEET2004ChemistryStructure of AtomActual
The frequency radiation emitted when the electron falls from n =4 to n=1 in a hydrogen atom will be (Given ionization energy of H =2.18 10⁻¹⁸ ~J atom ⁻¹ and h .=6.625 10⁻³⁴ Js ) :
Options
- A1.54 10¹⁵ ~s ⁻¹
- B1.03 10¹⁵ ~s ⁻¹
- C3.08 10¹⁵ ~s ⁻¹
- D2.00 10¹⁵ ~s ⁻¹
Correct answer
C. 3.08 10¹⁵ ~s ⁻¹
Step-by-step solution
E =h v or v = E h For H atom, aligned E & = -21.76 10⁻¹⁹ n^2 ~J ~atm ⁻¹ E & =-21.76 10⁻¹⁹ ( 1 4^2 - 1 1^2 ) aligned aligned & =20.40 10⁻¹⁹ ~J ~atm ⁻¹ v & = 20.40 10⁻¹⁹ 6.625 10⁻³⁴ & =3.079 10¹⁵ ~s ⁻¹ . aligned