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NEET 2018
Exam
NEET
Year
2018
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NEET 2018 · Physics · Center of Mass, Momentum and Collision

A moving block having mass m, collides with another stationary...

A moving block having mass m,m, collides with another stationary block having mass 4m.4m . The lighter block comes to rest after collision. When the initial velocity of the lighter block is v,v, then the value of coefficient of restitution (e)( e ) will be

Options

  1. A0.80.8
  2. B0.250.25
  3. C0.50.5
  4. D0.40.4

Correct answer

B. 0.250.25

Step-by-step solution

By conversation of linear momentum

mv=4mv′⇒v′=v4mv = 4m{v}^{′} ⇒ {v}^{′} = \dfrac{v}{4}

Coefficient of restitution (e)( e ) =VelocityofseparationVelocityofapproach= \dfrac{Velocityofseparation}{Velocityofapproach}

=v4−0v−0=14=0.25= \dfrac{\dfrac{v}{4} - 0}{v - 0} = \dfrac{1}{4} = 0.25
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