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NEET 2008
Exam
NEET
Year
2008
Subject
Physics
Chapter
Center of Mass, Momentum and Collision

NEET 2008 · Physics · Center of Mass, Momentum and Collision

Sand is being dropped on a conveyor belt at the rate of M ~kg / s ....

Sand is being dropped on a conveyor belt at the rate of M kg/sM \mathrm{~kg} / \mathrm{s}. The force necessary to keep the belt moving with a constant velocity of v m/sv \mathrm{~m} / \mathrm{s} will be

Options

  1. AMvM v newton
  2. B2Mv2 M v newton
  3. CMv2\frac{M v}{2} newton
  4. Dzero

Correct answer

A. MvM v newton

Step-by-step solution

Force required, F=d(mv)dt=v(dmdt)=vM\begin{aligned} F & =\frac{d(m v)}{d t} \\ & =v\left(\frac{d m}{d t}\right)=v M \end{aligned} as velocity vv is constant, hence F=Mv newton F=M v \text{ newton }
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