NEET2006PhysicsCenter of Mass, Momentum and CollisionActual
A 0.5 ~kg ball moving with a speed of 12 m / s strikes a hard wall at an angle of 30^ with the wall. It is reflected with the same speed at the same angle. If the ball is in contact with the wall for 0.25 seconds, the average force acting on the wall is:
Options
- A96 ~N
- B48 ~N
- C24 ~N
- D12 ~N
Correct answer
C. 24 ~N
Step-by-step solution
Applying law of conservation of momentum. Change in final momentum = initial momentum m v after collision -(-m v ) before collision aligned & f t= change in momentum =2 m v & f= 2 m v t aligned Putting the values we get, aligned f= & 2 0.5 12 30^ 0.25 & =24 ~N . aligned