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NEET2015PhysicsElectromagnetic WavesActual

A radiation of energy E falls normally on a perfectly reflecting surface. The momentum transferred to the surface is ( C = Velocity of light)

Options

  1. AE C
  2. B2 E C
  3. C2 E C 2
  4. DE C 2

Correct answer

B. 2 E C

Step-by-step solution

E = h C λ P = h λ     ⇒   P = E C Initial momentum of light when falls on a perfectly reflecting surface. P i = E C   When it is reflected momentum is in opposite direction P f = - E C Net momentum = P f - P i =   - E C - E C = - 2 E C Δ P = 2 E C

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