NEET2009PhysicsElectromagnetic WavesActual
The electric field part of an electromagnetic wave in a medium is represented by ( aligned & E_x=0 & E_y=2.5 NC ⁻¹ [ (2 10^6 rad s ⁻¹ ) t - ( 10⁻² rad m ⁻¹ ) x ] & E_z=0 aligned ) The wave is
Options
- Amoving along y direction with frequency 2 10^6 ~Hz and wavelength 200 ~m .
- Bmoving along x direction with frequency 10^6 ~Hz and wavelength 100 ~m
- Cmoving along x direction with frequency 10^6 ~Hz and wavelength 200 ~m
- Dmoving along -x direction with frequency 10^6 ~Hz and wavelength 200 ~m
Correct answer
A. moving along y direction with frequency 2 10^6 ~Hz and wavelength 200 ~m .
Step-by-step solution
Comparing the given equation aligned & E _ y =2.5 N C [ (2 10^6 rad m ) t . & .- ( 10⁻² rad sec ) x ] aligned With the standard equation E _ y = E ₀ ( t - kx ) we get array ll & =2 f =2 10^6 & f =10^6 ~Hz array Moreover, we know that aligned 2 & = k = 10⁻² ~m ⁻¹ & =200 ~m aligned Hence, the wave is moving along positive x -direction with frequency 10^6 ~Hz and wavelength 200 ~m .