Light with an energy flux of 25 × 10 ^ 4 Wm ^ - 2 falls on a...

Here, we have to calculate the average force calculated at the surface.

Given

I = $25 \times {10}^{4}$

A = $15 \times {10}^{- 4}$

We know that,

$F = \dfrac{2IA}{C} = \dfrac{2\left(25 \times {10}^{4}\right)\left(15 \times {10}^{- 4}\right)}{3 \times {10}^{8}} = 2.5 \times {10}^{- 6}N$

Hence, force will be $2.5 \times {10}^{- 6}N$

So Option (2) will be correct.