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Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V.S.D.) are equal to its 9 Main Scale Divisions (M.S.D.) The least division in the M.S. is 0.1 cm and the zero of V.S. is at x =0.1 ~cm when the jaws of Vernier callipers are closed. If the main scale reading for the diameter is M =5 ~cm and the number of coinciding vernier division

Options

  1. A5.18 cm
  2. B5.08 cm
  3. C4.98 cm
  4. D5.00 cm

Correct answer

C. 4.98 cm

Step-by-step solution

aligned & 10 V.S.D. =9 M.S.D. & 1 M.S.D. =0.1 ~cm (Given) & 1 V.S.D. =0.9 M.S.D. & 1 V.S.D. =0.9 0.1 ~cm & V.S.D. =0.09 ~cm & L.C. =1 M.S.D. -1 V.S.D. & =(0.1-0.09) cm & =0.01 ~cm & Reading =5.08 ~cm & Positive zero error =0.1 ~cm (Given) & Final Corrected reading =(5.08-0.1) cm & =4.98 ~cm aligned

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