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NEET 2026
Exam
NEET
Year
2026
Subject
Physics
Chapter
Gravitation

NEET 2026 · Physics · Gravitation

Two planets P_1 and P_2 with equal mass have radii R_1 and R_2 ,...

Two planets P1P_1 and P2P_2 with equal mass have radii R1R_1 and R2R_2, respectively, where R2=R12R_2=\dfrac{R_1}{2}. The escape speeds of P1P_1 and P2P_2 are v1v_1 and v2v_2, respectively. Then v2v1\dfrac{v_2}{v_1} is :

Options

  1. A22
  2. B12\dfrac{1}{\sqrt{2}}
  3. C11
  4. D2\sqrt{2}

Correct answer

D. 2\sqrt{2}

Step-by-step solution

The escape speed of a planet of mass MM and radius RR is given by v=2GMRv = \sqrt{\dfrac{2GM}{R}}.

For planet P1P_1, the escape speed is v1=2GMR1v_1 = \sqrt{\dfrac{2GM}{R_1}}.

For planet P2P_2, the escape speed is v2=2GMR2v_2 = \sqrt{\dfrac{2GM}{R_2}}.

Taking the ratio of the escape speeds:

v2v1=R1R2\dfrac{v_2}{v_1} = \sqrt{\dfrac{R_1}{R_2}}

Given that R2=R12R_2 = \dfrac{R_1}{2}, substituting this into the equation gives:

v2v1=R1R12=2\dfrac{v_2}{v_1} = \sqrt{\dfrac{R_1}{\dfrac{R_1}{2}}} = \sqrt{2}

Answer: 2\sqrt{2}
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