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NEET 2025
Exam
NEET
Year
2025
Subject
Physics
Chapter
Gravitation

NEET 2025 · Physics · Gravitation

The radius of Martian orbit around the Sun is about 4 times the...

The radius of Martian orbit around the Sun is about 4 times the radius of the orbit of Mercury. The Martian year is 687 Earth days. Then which of the following is the length of 1 year on Mercury?

Options

  1. A88 earth days
  2. B225 earth days
  3. C172 earth days
  4. D124 earth days

Correct answer

A. 88 earth days

Step-by-step solution

TMercury TMartian =(rMercury rMartian )3/2=(14)3/2=18TMercury =TMartian 8=6878=85.875 days ≈88 days \begin{aligned} & \frac{\mathrm{T}_{\text{Mercury }}}{\mathrm{T}_{\text{Martian }}}=\left(\frac{\mathrm{r}_{\text{Mercury }}}{\mathrm{r}_{\text{Martian }}}\right)^{3 / 2}=\left(\frac{1}{4}\right)^{3 / 2}=\frac{1}{8} \\ & \mathrm{ T}_{\text{Mercury }}=\frac{\mathrm{T}_{\text{Martian }}}{8}=\frac{687}{8}=85.875 \text{ days } \approx 88 \text{ days }\end{aligned}
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