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NEET 2019
Exam
NEET
Year
2019
Subject
Physics
Chapter
Laws of Motion

NEET 2019 · Physics · Laws of Motion

A block of mass 10kg is in contact against the inner wall of a...

A block of mass 10kg10kg is in contact against the inner wall of a hollow cylindrical drum of radius1m1m. The coefficient of friction between the block and the inner wall of the cylinder is 0.10.1. The minimum angular velocity needed for the cylinder to keep the block stationary when the cylinder is vertical and rotating about its axis will be (g=10ms−2)\left(g = 10m{s}^{- 2}\right),A block of mass 10kg is in contact against the inner wall of a hollow cylindrical drum of radius 1m . The coefficient

Options

  1. A10rads−1\sqrt{10}rad{s}^{- 1}
  2. B102πrads−1\dfrac{10}{2\pi}rad{s}^{- 1}
  3. C10rads−110rad{s}^{- 1}
  4. D10πrads−110\pi rad{s}^{- 1}

Correct answer

C. 10rads−110rad{s}^{- 1}

Step-by-step solution

A block of mass 10kg is in contact against the inner wall of a hollow cylindrical drum of radius 1m . The coefficient
N = m{ω}^{2}R
f=mgf = mg
For minimum angular velocity,
f = μN
mg = μ · m{ω}^{2}R
ω = \sqrt{\dfrac{g}{μR}} = \sqrt{\dfrac{10}{0.1 × 1}} = 10rad{s}^{- 1}
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