NEET2018PhysicsLaws of MotionActual
A block of mass m is placed on a smooth inclined wedge A B C of inclination θ as shown in the figure. The wedge is given an acceleration a towards the right. The relation between a and θ for the block to remain stationary on the wedge is
Options
- Aa = g cos θ
- Ba = s sin θ
- Ca = g cosce θ
- Da = g tan θ
Correct answer
D. a = g tan θ
Step-by-step solution
In non-inertial frame of wedge Using pseudo force, Free body diagram is given as Normal reaction is balanced by m g cos θ Where m is mass of the body, g is the acceleration due to gravity a is the acceleration produced by external force.. m a cos ⁡ θ = m g sin ⁡ θ a = g sin θ cos θ a = g tan ⁡ θ