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NEET 2018
Exam
NEET
Year
2018
Subject
Physics
Chapter
Laws of Motion

NEET 2018 · Physics · Laws of Motion

A block of mass m is placed on a smooth inclined wedge ABC of...

A block of mass m is placed on a smooth inclined wedge ABCABC of inclination θ\theta as shown in the figure. The wedge is given an acceleration aa towards the right. The relation between aa and θ\theta for the block to remain stationary on the wedge is

A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given

Options

  1. Aa=gcosθa = gcos \theta
  2. Ba=ssinθa = \dfrac{s}{sin \theta}
  3. Ca=gcosceθa = \dfrac{g}{cosce \theta}
  4. Da=gtanθa = gtan \theta

Correct answer

D. a=gtanθa = gtan \theta

Step-by-step solution

In non-inertial frame of wedge

Using pseudo force,
Free body diagram is given as


A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given
Normal reaction is balanced by mgcos(θ)mgcos\left(\theta\right)

Where m is mass of the body,

g is the acceleration due to gravity

a is the acceleration produced by external force..
macosθ=mgsinθmacos \theta = mgsin \theta

a=gsin(θ)cos⁡(θ)a = \dfrac{gsin\left(\theta\right)}{\cos \left(\theta\right)}

a=gtanθa = gtan \theta

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