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NEET 2015
Exam
NEET
Year
2015
Subject
Physics
Chapter
Laws of Motion

NEET 2015 · Physics · Laws of Motion

Three blocks A, B and C, of masses 4kg, 2kg 1kg and respectively,...

Three blocks A, B and C, of masses 4kg,2kg4kg, 2kg 1kg1kg and respectively, are in contact on a frictionless surface, as shown. If a force of 14N14N is applied on the4kg4kg block, then the contact force between A and B is:

Three blocks A, B and C, of masses 4kg, 2kg 1kg and respectively, are in contact on a frictionless surface, as shown.

Options

  1. A2N2N
  2. B6N6N
  3. C8N8N
  4. D18N18N

Correct answer

B. 6N6N

Step-by-step solution

F=Ma=(Ma+Mb+Mc)a14=(4+2+1)a=7aa=2\begin{aligned} & F=M a=\left(M_a+M_b+M_c\right) a \\ & 14=(4+2+1) a=7 a \\ & a=2 \end{aligned}) Let (F^{\prime}) bethethecontact force between (\mathrm{A} ~\&~ \mathrm{~B}), Three blocks A, B and C, of masses 4kg, 2kg 1kg and respectively, are in contact on a frictionless surface, as shown.F−F′=4a14−F′=4a=4×2F′=6N\begin{aligned} & F-F^{\prime}=4 a \\ & 14-F^{\prime}=4 a=4 \times 2 \\ & F^{\prime}=6 N\end{aligned}$
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