NEET2015PhysicsLaws of MotionActual
A rod of weight W is supported by two parallel knife edges A and B and is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A . the normal reaction on A is:
Options
- AW x d
- BW d x
- CW d - x x
- DW d - x d
Correct answer
D. W d - x d
Step-by-step solution
Equation for force balance N A + N B = W ...(i) N B = W - N A Equation for torque balance about centre of mass of rod. N A x = N B d - x N A x = W - N A d - x N A x = W d - W x - N A d + N A x N A d = W d - x N A = W d - x d