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NEET 2009
Exam
NEET
Year
2009
Subject
Physics
Chapter
Laws of Motion

NEET 2009 · Physics · Laws of Motion

A body, under the action of a force F =6 i -8 j +10 k , acquires an...

A body, under the action of a force F→=6i^−8j^+10k^\overrightarrow{\mathrm{F}}=6 \hat{\mathrm{i}}-8 \hat{\mathrm{j}}+10 \hat{\mathrm{k}}, acquires an acceleration of 1 m/s21 \mathrm{~m} / \mathrm{s}^2. The mass of this body must be :

Options

  1. A102 kg10 \sqrt{2} \mathrm{~kg}
  2. B210 kg2 \sqrt{10} \mathrm{~kg}
  3. C10 kg10 \mathrm{~kg}
  4. D20 kg20 \mathrm{~kg}

Correct answer

A. 102 kg10 \sqrt{2} \mathrm{~kg}

Step-by-step solution

F→=6i^−8j^+10k^∣F→∣=62+82+102=102m=∣F→∣a=1021=102kg\begin{aligned} \overrightarrow{\mathrm{F}}& =6 \hat{\mathrm{i}}-8 \hat{\mathrm{j}}+10 \hat{\mathrm{k}} \\ |\overrightarrow{\mathrm{F}}|& =\sqrt{6^2+8^2+10^2}=10 \sqrt{2}\\ \mathrm{ m}& =\frac{|\overrightarrow{\mathrm{F}}|}{\mathrm{a}}=\frac{10 \sqrt{2}}{1}=10 \sqrt{2} \mathrm{ kg} \end{aligned}
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