NEET2002PhysicsLaws of MotionActual
A block of mass 10 ~kg placed on the rough horizontal surface having coefficient of friction =0.5 , if a horizontal force of 100 ~N acting on it then acceleration of the block will be:
Options
- A10 ~ms ⁻¹
- B5 ~ms ⁻²
- C15 ~ms ⁻²
- D0.5 ~ms ⁻²
Correct answer
B. 5 ~ms ⁻²
Step-by-step solution
Here f_ = N= m g=0.5 10 10=50 ~N a= net force mass = 100-50 10 =5 ~m / sec ^2