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NEET 2002
Exam
NEET
Year
2002
Subject
Physics
Chapter
Laws of Motion

NEET 2002 · Physics · Laws of Motion

A block of mass 10 ~kg placed on the rough horizontal surface...

A block of mass 10 kg10 \mathrm{~kg} placed on the rough horizontal surface having coefficient of friction μ=0.5\mu=0.5, if a horizontal force of 100 N100 \mathrm{~N} acting on it then acceleration of the block will be:

Options

  1. A10 ms−110 \mathrm{~ms}^{-1}
  2. B5 ms−25 \mathrm{~ms}^{-2}
  3. C15 ms−215 \mathrm{~ms}^{-2}
  4. D0.5 ms−20.5 \mathrm{~ms}^{-2}

Correct answer

B. 5 ms−25 \mathrm{~ms}^{-2}

Step-by-step solution

Here fmax⁡=μN=μmg=0.5×10×10=50f_{\max }=\mu N=\mu m g =0.5 \times 10 \times 10=50N\mathrm{ N}\Rightarrow a=\frac{ net force \text{ net force }}{ mass \text{ mass }} =100−5010=\frac{100-50}{10}=5 m\mathrm{ m} / sec2\mathrm{sec}^2
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