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NEET 2013
Exam
NEET
Year
2013
Subject
Physics
Chapter
Laws of Motion

NEET 2013 · Physics · Laws of Motion

A car is moving in a circular horizontal track of radius 10 ~m the...

A car is moving in a circular horizontal track of radius 10 m10 \mathrm{~m} the roof of the car by a light wire of length 1.0 m1.0 \mathrm{~m}. The angle made by the wire with the vertical is: A car is moving in a circular horizontal track of radius 10 ~m the roof of the car by a light wire of length 1.0 ~m .

Options

  1. Aπ3\frac{\pi}{3}
  2. Bπ6\frac{\pi}{6}
  3. Cπ4\frac{\pi}{4}
  4. D0∘0^{\circ}

Correct answer

C. π4\frac{\pi}{4}

Step-by-step solution

From the question v=10m/s,r=10m,g=10m/s2v=10 \mathrm{ m} / \mathrm{s}, \mathrm{r}=10\mathrm{m}, \mathrm{g}=10 \mathrm{ m} / \mathrm{s}^2 If θ=\theta= angle made by wire with vertical then tan⁡θ=V2rg=10×1010×10=1tan⁡θ=1⇒θ=tan⁡−1(i)=π4\begin{aligned} \tan \theta& =\frac{V^2}{r g}\\ & =\frac{10 \times 10}{10 \times 10}=1 \\ \tan \theta=1 \Rightarrow \theta=\tan ^{-1}& (\mathrm{i})=\frac{\pi}{4} \end{aligned}
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