NEET2013PhysicsMagnetic Effects of CurrentActual
A long straight wire carries a certain current and produces a magnetic field 2 10⁻⁴ Weber m ^2 at a perpendicular distance of 5 ~cm from the wire. An electron situated at 5 ~cm from the wire moves with a velocity 10^7 ~m / s towards the wire along perpendicular to it. The force experienced by the electron will be (change on electron 1.6 10⁻¹⁹ C )
Options
- A3.2 ~N
- B3.2 10⁻¹⁶ ~N
- C1.6 10⁻¹⁶ ~N
- DZero
Correct answer
B. 3.2 10⁻¹⁶ ~N
Step-by-step solution
From the question Velocity of electron =10^7 ~m / s Magnetic field B=2 10⁻⁴ ~Wb / m ^2 Then magnitude of force experienced by the electron i.e. F=e v ~B V and B are prependicular to each other aligned & =e v ~B 90^ & =1.6 10⁻¹⁹ 10^7 2 10⁻⁴ 1 & =3.2 10⁻¹⁶ ~N aligned