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NEET2012PhysicsMagnetic Effects of CurrentActual

A proton carrying 1 MeV kinetic energy is moving in a circular path of radius R in uniform magnetic field. What should be the energy of an -particle to describe a circle of same radius in the same field?

Options

  1. A2 MeV
  2. B1 MeV
  3. C0.5 MeV
  4. D4 MeV

Correct answer

B. 1 MeV

Step-by-step solution

For proton r= 2 m( KE ) q B So q m( KE ) Hence aligned e 2 e & = (m_p )(1 MeV ) (4 m_p )( KE ) 1 4 & = 1 MeV 4 KE KE & =1 MeV aligned

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